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26-05-2016
Mathematics

Answered

Seperate the number 53 into 3 parts so that the second number is 3 less than the first number and the third number is twice the first number. Give the value of the second number.

Verified Answer :

28-05-2016

Hello,

Let a the first, b the second and c the third.
a+b+c=53
b=a/3
c=2a
==>a+a/3+2a=53
==>10a/3=53
==>a=15.9
c=2a=215.9=31.8
b=a/3=15.9/3=5.3

Proof: a+b+c=15.9+5.3+31.8=53

The second number is 5.3

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