The basis of this cone is a circle with a diameter d = 16m. This information is sufficient to calculate
1. The surface of the wheel . We use the formula
\(A = \pi r^{2}\)
2. the radius of the wheel needed to the formula for calculating the area of a circle and the cone
d = 16m
1/2d = r = 1/216m = 8m
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Area base
\(P = \pi r^{2} = \pi (8m)^{2} = 64 \pi m^{2}\)
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The surface area
\(A = \pi rl\)
l - creates a cone = ?
Height , forming a cone and the radius of a circle formed triangle . Two known sides is possible to calculate the third side ( the cone ) of the Pythagorean Theorem
a = r = 8cm
b = h = 24m
c = l = ?
a² + b² = c²
r² + h² = l²
l = √ (r² + h²) = √ [ ( 8m)² + ( 24m)² ] = √ (64m² + 576m²) = √ (640 m²)= √ (8810m²) = 8√10m
The lateral surface of the cone
A = πrl = π8m 8√10m = 64√10πm²
The total area of the cone = The base area of the side surface of +
A = 64√10πm² + 64πm² = 64πm² (√10 + 1)
