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Answered

A construction worker pushes a wheelbarrow 5.0 m with a horizontal force of 50.0 N. How much work is done by the worker on the wheelbarrow

Verified Answer :

Work Done = force • distance
Work Done = 5m • 50N
Work Done = 250J

Answer: 250 Joules

Cricetus

The work done will be "250 J".

According to the question,

  • Force, F = 50 N
  • Distance, d = 5 m

The work done is:

→ \(Work \ done = Force\times Distance\)

or,

→                \(W = F\times D\)

By substituting the values, we get

                      \(= 50\times 5\)

                      \(= 250 \ J\)

Thus the above response is correct.  

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https://brainly.com/question/21386378

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