The temperature of the gas is about 600 K
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Further explanation
The Ideal Gas Law that needs to be recalled is:
\(\large {\boxed {PV = nRT} }\)
P = Pressure (Pa)
V = Volume (m³)
n = number of moles (moles)
R = Gas Constant (8.314 J/mol K)
T = Absolute Temperature (K)
Let us now tackle the problem !
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Question (Translation):
A total of 0.2 moles of ideal gas are in containers with volume of 10 liters and a pressure of 1 atm. What is the temperature of the gas?
Given:
number of moles = n = 0.2 moles
volume of gas = V = 10 liters
pressure of gas = P = 1 atm
gas contant = R = 0.0821 L.atm/mol.K
Unknown:
temperature of gas = T = ?
Solution:
\(PV = nRT\)
\(1 \times 10 = 0.2 \times 0.0821 \times T\)
\(10 = 0.01642 \times T\)
\(T = 10 \div 0.01642\)
\(T \approx 600 \texttt{ K}\)
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Learn more
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Answer details
Grade: High School
Subject: Physics
Chapter: Pressure
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Keywords: Gravity , Unit , Magnitude , Attraction , Distance , Mass , Newton , Law , Gravitational , Constant , Liquid , Pressure
