The length of s is 2/3 the length of t. If s has an area of 368 cm squared find the perimeter of the figure
\(s = \frac{2}{3}t \\\ \frac{2}{3}t*t = \frac{2}{3}t^2 \\\ \frac{2}{3}t^2 = 368 \\\ t^2 = \frac {3}{2}368 \\\ t^2 = 552 \\\ t \approx 23.5 \\\ s \approx 15.6 \\\ P \approx 78.2\)