Verified Answer :

Ckaranja

(1,7)

Working;
Start by finding the derivative of the function f(x);
\(f^{'} (x)\)=2x-2
Turning points occur when the derivative function=0;
Thus
2x-2=0
x=1
when x=1 then
f(1)=\(1^{2} -2(1)+8\)
=7
Turning point then is (1,7)

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