The solution of 2cos2x + cosx − 1 = 0 is \(x=\pi.\)
What is a Trigonometric equation?
A Trigonometric equation is an equation involving one or more trigonometric ratios of unknown angles.
How to solve?
2cos2x + cosx − 1 = 0
\(-3+\cos \left(x\right)+4\cos ^2\left(x\right)=0\)
\(\cos \left(x\right)=\frac{3}{4},\:\cos \left(x\right)=-1\)
And now,
\(x=\pi +2\pi n\)
Which is only \(x=\pi\).
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