Answer:
The correct option is b.
Step-by-step explanation:
We have to find the product of \(\frac{2a-7}{a}\) and \(\frac{3a^2}{2a^2-11a+14}\).
Multiply both terms.
\(\frac{2a-7}{a}\times \frac{3a^2}{2a^2-11a+14}\)
Cancel out the common factor a from numerator and denominator.
\(\frac{2a-7}{1}\times \frac{3a}{2a^2-7a-4a+14}\)
\(\frac{2a-7}{1}\times \frac{3a}{a(2a-7)-2(2a-7)}\)
\(\frac{2a-7}{1}\times \frac{3a}{(2a-7)(a-2)}\)
Cancel out the common factor (2a-7) from numerator and denominator.
\(\frac{1}{1}\times \frac{3a}{a-2}\)
\(\frac{3a}{a-2}\)
Therefore, the correct option is b.
