Decompose -6x/(x+4)(x-4) into partial fractions
Hello,Integration fractions?-6x/((x+4)(x-4))=A/(x+4)+B/(x-4)=((A+B)x-4A+4B)/((x+4)(x-4))==> A+B=-6 and -4A+4B=0==>A=B=-3Answer -3/(x+4)-3/(x-4)