remember
\(log_{b}m^{n}=nlog_{b}m\)
\(1/4log_{5}81=log_{5}81^{1/4}=log_{5}3\)
\(1/2log_{5}64=log_{5}64^{1/2}=log_{5}8\)
we now have
\(log_{5}n=log_{5}3+log_{5}8\)
remember
\(log_{b}m+log_{b}n= log_{b}(mn)\) so
\(log_{5}3+log_{5}8= log_{5}(3*8)=log_{5}24\)
\(log_{5}n=log_{5}24\)
therefor n=24
