Verified Answer :

There are 6 kittens when you're deciding which one you want to pick, so there are 6 ways of chosing one. Then, the number of kittens lowers to 5, so there are 5 ways of picking another. At all, there are 30 ways of chosing 2 kittens out of 6.

There are 15 ways to choose 2 of the kittens from the litter

How to determine the number of ways?

The given parameters are:

  • Litter = 6
  • To select = 2

The number of ways to select the 2 kittens is:

Ways = \(^nC_r\)

This gives

Ways =  \(^6C_2\)

The combination formula is:

\(^nC_r = \frac{n!}{(n - r)!r!}\)

So, we have:

\(^6C_2 = \frac{6!}{(6 - 2)!2!}\)

Evaluate the difference

\(^6C_2 = \frac{6!}{4!2!}\)

Expand

\(^6C_2 = \frac{6 * 5 * 4!}{4! * 2 * 1}\)

Evaluate the quotient

\(^6C_2 = 15\)

So, we have:

Ways = 15

Hence, there are 15 ways to choose 2 of the kittens from the litter

Read more about combination at:

https://brainly.com/question/11732255

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