Which equation has an a-value of 1, a b-value of –3, and a c-value of –5?
Answer:
\(x^2-3x-5\)
Step-by-step explanation:
The standard quadratic equations are given in the form of
\(ax^2+bx+c\)
Comparing the values of a , b and c and putting a=1 , b=-3 and c=-5 in the equation we get our quadratic polynomial as
\(x^2-3x-5\)