I can do both
remember
(ab)/(cd)=(a/c)(b/d)=(a/d)(b/c)
also exponential laws
(x^m)/(x^n)=x^(m-n)
and
(x^m)^n=x^(mn)
and
x^-m=1/(x^m)
and
(xyz)^m=(x^m)(y^m)(z^m)
first apply the exponents outside
(3x^-1y)^-2=(3^-2)((x^-1)^-2)(y^-2)=(1/9)x^2y^-2
bottom
(2x^2y^-2)^3=(2^3)((x^2)^3)((y^-2)^3)=8x^6y^-6
now we have
\(\frac{ (1/9)x^{2}y^{-2}}{8x^{6}y^{-6}}\)
that equals
\(( \frac{1/9}{8} )( \frac{x^{2}}{x^{6}})( \frac{y^{-2}}{y^{-6}} )\) then
2-6=-4
-2-(-6)=4
\(( \frac{1}{72} )( \frac{1}{x^{4}})( \frac{1}{y^{4}} )\)=
\(\frac{y^{4}}{72x^{4}}\)
