Answer:
The probability that both of the shirts are black is \(\frac{1}{15}\)
Step-by-step explanation:
Given : Henry has 3 black shirts and 7 blue shirts in his wardrobe. Two shirts are drawn without replacement from the wardrobe.
To find : What is the probability that both of the shirts are black?
Solution :
Number of black shirts = 3
Number of blue shirt = 7
Total number shirts = 3+7=10
The probability that first shirts is black is \(\frac{3}{10}\)
Two shirts are drawn without replacement from the wardrobe.
Number of black shirt left = 2
Total shirts = 9
The probability that second shirts is black is \(\frac{2}{9}\)
So, The probability that both of the shirts are black is
\(P=\frac{3}{10}\times\frac{2}{9}\)
\(P=\frac{6}{90}\)
\(P=\frac{1}{15}\)
