Verified Answer :


  1. seems to be a geometric sequence
    common ratio is -4
    first erm is -2
    \(a_{n}=-2(-4)^{n-1}\)


    5. x=-1
    remember x^-1=1/x
    f(-1)=4(7^-1)=4(1/7)=4/7
    f(2)=4(7^2)=4(49)=196


    6. remember
    (ab)/(cd)=(a/c)(b/d)
    also
    (x^m)/(x^n)=x^(m-n)
    and
    (x^m)(x^n)=x^(m+n)

    so
    \(\frac{4.5*10^{3}}{9*10^{7}}\)=
    (\(\frac{4.5}{9}\))(\(\frac{10^{3}}{10^{7}}\))=
    (0.5)(\(10^{3-7}\)=
    (0.5)(10^-4)=
    (5)(10^-1)(10^-4)=
    (5)(10^(-1-4)
    5*10^-5






    4. \(a_{n}=-2(-4)^{n-1}\)

    5. f(-1)=4/7
    f(2)196

    6. 5 times 10^-5