Verified Answer :

Willchemistry

1 mole --------- 6.02 x 10²³ molecules
? mole --------- 4.00 x 10²³ molecules

moles =  (4.00 x 10²³) x 1 / 6.02 x 10²³

moles = ( 4.00 x 10²³) / ( 6.02 x 10²³ )

= 0.6644 moles

Molar mass H₃PO₄ = 98.0 g/mol

mass = 0.6644 x 98.0 = 65.1112 g

hope this helps!

Answer : The approximate mass of \(H_3PO_4\) is 65 grams.

Explanation :

First we have to calculate the moles of \(H_3PO_4\).

As, \(6.022\times 10^{23}\) molecules of \(H_3PO_4\) present in 1 mole of \(H_3PO_4\)

So, \(4.00\times 10^{23}\) molecules of \(H_3PO_4\) present in \(\frac{4.00\times 10^{23}}{6.200\times 10^{23}}=0.664\) mole of \(H_3PO_4\)

Now we have to calculate the mass of \(H_3PO_4\).

\(\text{Mass of }H_3PO_4=\text{Moles of }H_3PO_4\times \text{Molar mass of }H_3PO_4\)

Molar mass of \(H_3PO_4\) = 98 g/mole

\(\text{Mass of }H_3PO_4=0.664mole\times 98g/mole=65.072g\approx 65g\)

Therefore, the approximate mass of \(H_3PO_4\) is 65 grams.

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