Football player A has a mass of 210 pounds and is running at a rate of 5.0 mi/hr. He collides with player B. Player B has a mass of 190 pounds and is running in the same direction at 3.0 mi/hr. Which of the following statements is true?

-The momentum of player A is equal to that of player B.

-The momentum of player A is greater than that of player B.

-The momentum of player A is less than that of player B.

The equation for momentum is p =
mv where p is the omentum, m is the mass and v is the velocity. Calculating the
momentum for each football player, player A will have a momentum of 1050
lb-mi/h and player B will have a momentum of 570 lb-mi/h. Therefore, momentum of player A is greater than that of
player B.

Answer Link

flightbath flightbath · Answer 2 · 2018-12-19T02:22:38-05:00

Answer:

the momentum of player A is greater than player B.

Therefore, Option 2 is correct.

Step-by-Step explanation:

We have been given the velocity of the players and mass of the players.

Player A:

Velocity is 5m/hr

Mass 210 pounds

Player B:

Velocity is 3m/hr

Mass 190 pounds

We have a formula for momentum:

$p=mv$

p is momentum

m is mass

v is velocity

We will find momentums for both the players:

Momentum of player A:

on substituting the values we get:

$p=210\cdot 5=1050 pounds$

Momentum of player B:

on substituting the values we get:

$p=190\cdot 3=570 pounds$

Hence, the momentum of player A is greater than player B.

Therefore, Option 2 is correct.