Answer : The correct option is, (C) 50 grams
Solution :
Formula used :
\(a=\frac{a_o}{2^n}\)
where,
a = amount of reactant left after n-half lives = ?
\(a_o\) = Initial amount of the reactant = 100 g
n = number of half lives = 1
Putting values in above equation, we get:
\(a=\frac{100}{2^1}\)
\(a=50g\)
Therefore, the amount of uranium-238 remain will be, 50 g
