can you help me with these please
Hello1)\(\frac{2x(x-3)}{(x-1)(x+1)}*\frac{x(x-1)}{(x-3)}*\frac{3(x+1)}{1}\)\(=\frac{6x(x+1)}{x+1}=6x\)2)\(\frac{2(x-1)-(x+1)-(x+2)}{(x-1)(x+1)(x+2)}=\frac{-5}{(x-1)(x+1)(x+2)}\)
