A blue-light photon has a wavelength of 4.80 × 10-7 meter. What is the energy of the photon?

The energy of a photon is
presented in the equation of E = hc/gamma where E is the energy of the photon,
hc is 1.99x10^-25 joules – meter and gamma is the wavelength of the photon. Since
you are given a blue-light photon with a wavelength of 4.80 × 10-7 meter, plug
in the values to the energy equation and you will get 4.15x10^-19 joules.

Answer Link

aristocles aristocles · Answer 2 · 2019-05-27T21:52:09-04:00

Answer:

\(Energy = 4.125 \times 10^{-19} J\)

\(Energy = 2.6 eV\)

Explanation:

As we know that energy associated with a photon is given by

\(Energy = \frac{hc}{\lambda}\)

here we know that

\(h = 6.6 \times 10^{-34}\)

c = speed of light

now we have

\(\lambda = 4.80 \times 10^{-7} m\)

now we will have

\(E = \frac{(6.6 \times 10^{-34})(3 \times 10^8)}{4.80 \times 10^{-7}}\)

\(E = 4.125 \times 10^{-19} J\)

now we can also convert it into electron volt

\(E = \frac{4.125 \times 10^{-19}}{1.6 \times 10^{-19}} = 2.6 eV\)