What polynomial identity will prove that 49 = (2+5)^2? (A. Difference of Squares; B. Difference of Cubes; C. Sum of Cubes; D. Square of a Binomial)
Hi,
(a+b)² = a²+2ab+b²
For a = 2 and b = 5
(2+5)² = 2²+2(2)(5)+5²
(2+5)² = 4+20+25
(2+5)² = 49
Answer:
D. Square of a Binomial
Answer:
Option D is correct.
Square of binomials.
Step-by-step explanation:
Prove that: \(49 = (2+5)^2\)
Square of binomials states that the square of a binomial is always a trinomial.
Also, it will be helpful to memorize these patterns for writing squares of binomials as trinomials.
\((a+b)^2 = a^2+2ab+b^2\)
Take RHS
\((2+5)^2\)
Apply the square of binomial, we have;
\((2+5)^2 = 2^2+2 \cdot 2 \cdot 5 +5^2\)
= 4 + 20 + 25 = 24 + 25 = 49 = LHS proved.
Therefore, Square of binomials identity will prove that \(49 = (2+5)^2\)