ok rmemeber
√(a/b)=(√a)/(√b)
and
√ab=(√a)(√b)
and
(a^m)/(a^n)=a^(m-n)
so
ignore 11 for now, we will get to that at end
\(\sqrt{ \frac{49a^{5}}{4a^{3}}}\)=
\(\frac{\sqrt{49a^{5})}{\sqrt{4a^{3}}}\)=
\(\frac{(\sqrt{49})(\sqrt{a^{5}})}{(\sqrt{4)(\sqrt{a^{3}}}\)=
\(\frac{(7)(a^{2} \sqrt{a}) }{(2)(a \sqrt{a}) }\)=
\(\frac{7a^{2} \sqrt{a} }{2a \sqrt{a} }\)=
\(\frac{7a}{2}\)
