Lo7veB4stude
Answered

Which second degree polynomial function has a leading coefficient of –1 and root 4 with multiplicity 2?


f(x) = –x2 – 8x – 16


f(x) = –x2 + 8x – 16


f(x) = –x2 – 8x + 16


f(x) = –x2 + 8x + 16

Verified Answer :

caylus

Hello,

f(x)=-(x-4)²=-(x²-8x+16)=-x²+8x-16

Answer B

Answer:

The answer is B. Just took the test.

Step-by-step explanation:

Related Questions