The missing value is 3 because roots of the function f(x) = x2 – 2x – 3 are -1 and 3
What is a quadratic equation ?
Any equation of the form \(\rm ax^2+bx+c=0\) where x is variable and a, b, and c are any real numbers where a ≠ 0 is called a quadratic equation.
As we know, the formula for the roots of the quadratic equation is given by:
\(\rm x = \dfrac{-b \pm\sqrt{b^2-4ac}}{2a}\)
We have a function:
f(x) = x² – 2x – 3
Equate the function to zero;
f(x) = 0
x² – 2x – 3 = 0
a = 1, b = -2, c = -3
\(\rm x = \dfrac{-(-2) \pm\sqrt{-2^2-4(1)(-3)}}{2(1)}\)
After simplification:
\(\rm x = \dfrac{2 \pm\sqrt{16}}{2}\)
x = 3 or x = -1
Thus, the missing value is 3 because roots of the function f(x) = x2 – 2x – 3 are -1 and 3
Learn more about quadratic equations here:
brainly.com/question/2263981
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