Verified Answer :

We know that

if the point belongs to the graph, then it must satisfy the given function.

We proceed to verify each of the points

we have

\(f(x) = 7 - 3x\)

case a) \((-2, 1)\)

\(x=-2\\y=1\)

Substitute the value of x in the given function and compare the value of f(x) with the value of the coordinate y of the point

\(f(x) = 7 - 3*(-2)\)

\(f(x) = 13\)

\(13 eq 1\) --------> the point not lie on the graph

case b) \((-1, 10)\)

\(x=-1\\y=10\)

Substitute the value of x in the given function and compare the value of f(x) with the value of the coordinate y of the point

\(f(x) = 7 - 3*(-1)\)

\(f(x) = 10\)

\(10=10\) --------> the point  lie on the graph

case c) \((0, 7)\)

\(x=0\\y=7\)

Substitute the value of x in the given function and compare the value of f(x) with the value of the coordinate y of the point

\(f(x) = 7 - 3*(0)\)

\(f(x) = 7\)

\(7=7\) --------> the point lie on the graph

case d) \((1, 5)\)

\(x=1\\y=5\)

Substitute the value of x in the given function and compare the value of f(x) with the value of the coordinate y of the point

\(f(x) = 7 - 3*(1)\)

\(f(x) = 4\)

\(4 eq 5\) --------> the point not lie on the graph

case e) \((2, 1)\)

\(x=2\\y=1\)

Substitute the value of x in the given function and compare the value of f(x) with the value of the coordinate y of the point

\(f(x) = 7 - 3*(2)\)

\(f(x) = 1\)

\(1=1\) --------> the point lie on the graph

therefore

the answer is

Points that lie on the graph are

\((-1, 10)\)

\((0, 7)\)

\((2, 1)\)

see the attached figure to better understand the problem


View image calculista

Answer:

So the person above me got it right (I think)  but im small brain and dont wanna read all that so for all the ppl like me the answer is

(-1, 10)

(0, 7)

(2, 1).

Your welcome fellow lazy ppls :3