Verified Answer :

apologiabiology

nice, already in vertex form
y=a(x-h)^2+k
(h,k) is vertex

therfor since (-3,6) is vertex
we are looking for something like
y=a(x-(-3))^2+6 simplified to
y=a(x+3)^2+6


A is ansre

SchwarzschildRadius

So,

The vertex form of a parabola is:

\(y=a(x-h)^2+k\)

and the vertex is at (h,k).

Thus, the equation will have to look something like this:

\(y=a(x+3)^2+6\)

Only option A matches these criteria, so is must be the correct option.

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