To solve, lets find the volumes of all of the options...
V=lwh
A.
634=72cm³
1223=72cm³
B.
249=72cm³
942=72cm³
C.
338=72cm³
268=96cm³
D.
634=72cm³
943=108cm³
We can conclude that C & D aren't the answer, since they contain prisms that don't have a volume of 72cm³.
Now lets solve for the surface area of A and B...
A.
sA=2(wh+lw+lh)=2(63+46+43)=2(18+24+12)=2(54)=108cm²
sA=2(wh+lw+lh)=2(122+312+32)=2(24+36+6)=2(56)=112cm²
B.
sA=2(wh+lw+lh)=2(24+92+94)=2(8+18+36)=2(62)=124cm²
sA=2(wh+lw+lh)=2(94+29+24)=2(36+18+8)=2(62)=124cm²
A is the only option with both similar volumes of 72cm³ and different surface areas...
Answer=A
