Answer:
Cube root of \(27x^{18}\) is \(3x^{6}\)
Step-by-step explanation:
We need to find the cube root of the expression \(27x^{18}\)
Take a cube root over \(27x^{18}\)
\(\sqrt[3]{27x^{18}}\)
\(\sqrt[3]{3^{3}(x^{6})^{3}}\)
simplify the above expression,
\(\sqrt[3]{(3x^{6})^{3}}\)
\(3x^{6}\)
Hence, cube root of \(27x^{18}\) is \(3x^{6}\)
