solve 7(k- 3) = 3k - 5
\(7(k- 3) = 3k - 5\\7(k)-7(3) = 3k-5\\7k - 21=3k-5\\7k-3k-21 =3k-3k-5\\4k-21=-5\\4k-21+21=-5+21\\4k=16\\\frac{4k}{4} =\frac{16}{4}\\\\\boxed{\bf{k=4}}\)
