Answer:
The answer is the option B
\(y=4x+11\)
Step-by-step explanation:
we know that
The equation of the line into slope point form is equal to
\(y-y1=m(x-x1)\)
in this problem we have
\(m=4\)
\(point(-3,-1)\)
substitute
\(y-(-1)=4(x-(-3))\)
\(y+1=4(x+3)\) ---> equation of the line into slope point form
isolate the variable y
\(y=4x+12-1\)
\(y=4x+11\) ---> equation of the line into slope intercept form
