Verified Answer :

garydesir1

Good evening


x^0+y^0 for x=3 and y=2

First thing we need to do is to replace their value

3^0+2^0

Remember: Any number that raised to the zero power equal 1

so now we have

3^0=1 and y^2=1

1+1

= 2


I hope that's help :0


Any Questions /

 

Answer:

The value of given expression is 2

Step-by-step explanation:

Given: Expression is \(x^0+y^0\)

To find : Value of expression when x = 3 and y = 2

Consider,

\(x^0+y^0\)

To find value we put value of x = 3 and y = 2

\(\implies 3^0+2^0\)

Now we know that value of expression whose power 0 is 1 irrespective of value of base .i.e, \(a^0=1\) ∀ a ∈ any no.

⇒\(3^0=1\:and\:2^0=1\)

\(\implies 3^0+2^0\) = 1 + 1

⇒ 2

Therefore, The value of given expression is 2

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