The number of chips of different colors in Gail's bag is shown below:

3 blue chips

4 pink chips

8 white chips

Gail takes out a chip from the bag randomly without looking. She replaces the chip and then takes out another chip from the bag. What is the probability that Gail takes out a white chip in both draws?

A.\(\frac{8}{15}\)+\(\frac{7}{14}\)=\(\frac{217}{210}\)

B.\(\frac{8}{15}\)×\(\frac{7}{14}\)=\(\frac{56}{210}\)

C.\(\frac{8}{15}\)+\(\frac{8}{15}\)=\(\frac{16}{15}\)

D.\(\frac{8}{15}\)×\(\frac{8}{15}\)=\(\frac{64}{225}\)

Verified Answer :

most likely the probability is D because my mom said it is d i dont know how she got it

Answer:

\(\frac{8}{15} \times \frac{8}{15}=\frac{64}{225}\)

Step-by-step explanation:

Given : 3 blue chips

            4 pink chips

            8 white chips

To Find:  What is the probability that Gail takes out a white chip in both draws with replacement?

Solution:

Blue chips  =3

Pink chips  =4

White chips =8

Total chips = 3+4+8 =15

Now Probability of getting white chip on first draw = \(\frac{\text{Number of white chips }}{\text{Total no. of chips}}\)

                                                                                   = \(\frac{8}{15}\)  

Now ,She replaces the chip and then takes out another chip from the bag.

So, Probability of getting white chip on second draw = \(\frac{8}{15}\)  

Probability of getting white chip in both draws = \(\frac{8}{15} \times \frac{8}{15}=\frac{64}{225}\)

Hence the probability that Gail takes out a white chip in both draws is \(\frac{8}{15} \times \frac{8}{15}=\frac{64}{225}\)

Thus Option D is correct.