The other charge of the particle given the data from the question is 8 μC
Data obtained from the question
- Force (F) = 7.2 N
- Distance apart (r) = 0.2 m
- Electrical constant (K) = 9×10⁹ Nm²/C²
- Charge on 1st particle (q₁) = 4 μC = 4×10¯⁶ C
- Charge on 2nd particle (q₂) = ?
How to determine the 2nd charge
The charge on the other particle can be obtained by using the Coulomb's law equation as shown below:
F = Kq₁q₂ / r²
7.2 = (9×10⁹ × 4×10¯⁶ × q₂) / 0.2²
7.2 = (9×10⁹ × 4×10¯⁶ × q₂) / 0.04
Cross multiply
9×10⁹ × 4 × q₂ = 7.2 × 0.04
Divide both side by 9×10⁹ × 4×10¯⁶
q₂ = (7.2 × 0.04) / (9×10⁹ × 4×10¯⁶)
q₂ = 8×10¯⁶ C
q₂ = 8 μC
Learn more about Coulomb's law:
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