\(4b^2+8b+7=4\)
Quadratic equation formula:
For a quadratic equation of the form \(ax^2+bx+c=0\)
the solution are:
\(x_1,2= \frac{-b \frac{+}{-} \sqrt{b^2-4*a*c} }{2*a}\)
for a = 4 , b = 8 , c = 3
\(b_1,2= \frac{-8 \frac{+}{-} \sqrt{8^2-4*4*3} }{2*4}\)
\(b= \frac{-8+ \sqrt{8^2-4*4*3}}{2*4} =- \frac{1}{2}\)
\(b= \frac{-8- \sqrt{8^2-4*4*3} }{2*4} = -\frac{3}{2}\)
The final solutions to the quadratic equation are:
\(b= -\frac{1}{2} ,b=- \frac{3}{2}\)
hope this helps!
