What is the simplified value of the exponential expression 16^1/4?
2
First, we are going to use the law of fractional exponents: \(a^{\frac{1}{n} =\sqrt[n]{a}\)
We can infer form our expression that \(a=16\) and \(n=4\), so let's replace the values:
\(a^{\frac{1}{n} =\sqrt[n]{a}\)
\(16^{\frac{1}{4} }=\sqrt[4]{16}\)
Notice that we can also decompose 16 into prime factors to get \(16=2^4\), so we can rewrite our expression as follows:
\(\sqrt[4]{16}=\sqrt[4]{2^4}\)
Finally, we can use the rule of radicals: \(\sqrt[n]{a^n} =a\), so:
\(\sqrt[4]{2^4}=2\)
The simplified value of the exponential expression \(16^\frac{1}{4}\) is \(2\).
Fractional power implies the root of the strength of the denominator of that integer.
For example: \(a^\frac{1}{n}=\sqrt[n]{a}\).
Given here the exponential expression is \(16^\frac{1}{4}\)
So here \(a=16,n=4\)
We know that, \(2^4=16\)
Thus, \(16^\frac{1}{4}=\sqrt[4]{16}=\sqrt[4]{2^4}=2\)
Hence the equivalent value of the given expression \(16^\frac{1}{4}\) is 2.
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