What is the Turing point of f(x)=x^2-2x+8
method1:parabola y = x^2 - 2x + 8 y-7 = (x-1)^2 ; parabola turning point is (1,7) method2:diff y = x^2 - 2x + 8 y' = 2x -2 = 0 ==> x = 1, y=7