How to show your work to solve 3r^2-16r-7=5
OK so 3r^2-16r-7=5 Subtract five from both sides 3r^2-16r-7-5=0 Add like terms 3r^2-16r-12=0 Factorise it, this means putting it into brackets (3r + 2)(r - 6) Find out what multiplies to make negative twelve but adds to make negative sixteen However none of the terms do this so we put negatives next to the "r"s (-3r + 2)(-1r - 6) The answer is r=6
Answer:
Step 1: Subtract 5 from both sides.
3r2−16r−7−5=5−5
3r2−16r−12=0
Step 2: Factor left side of equation.
(3r+2)(r−6)=0
Step 3: Set factors equal to 0.
3r+2=0 or r−6=0
r=−2/3
or r=6
Step-by-step explanation:
