A bag contains 6 blue marbles, 4 red marbles, and 2 yellow marbles. What is the probability of selecting a blue marble, replacing it, then selecting another blue marble?
i think there is a .5 percent chance i added all numbers and divided by 6[the blue marbles]
Probabilities are used to determine the chances of an event.
The probability of selecting 2 blue marbles (with replacement) is 1/4
The given parameters are:
\(\mathbf{Blue = 6}\\\\\)
\(\mathbf{Red = 4}\)
\(\mathbf{Yellow = 2}\)
The total number of marbles is:
\(\mathbf{n =Blue + Red + Yellow }\)
\(\mathbf{n =6 + 4 + 2}\)
\(\mathbf{n =12}\)
The probability of selecting 2 blue marbles (with replacement) is:
\(\mathbf{Pr = \frac{Blue}{n} \times \frac{Blue}{n}}\)
\(\mathbf{Pr = \frac{6}{12} \times \frac{6}{12}}\)
Simplify
\(\mathbf{Pr = \frac{1}{2} \times \frac{1}{2}}\)
Multiply
\(\mathbf{Pr = \frac{1}{4}}\)
Hence, the probability of selecting 2 blue marbles (with replacement) is 1/4
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