A bag contains 6 blue marbles, 4 red marbles, and 2 yellow marbles. What is the probability of selecting a blue marble, replacing it, then selecting another blue marble?

Verified Answer :

i think there is a .5 percent chance i added all numbers and divided by 6[the blue marbles]

Probabilities are used to determine the chances of an event.

The probability of selecting 2 blue marbles (with replacement) is 1/4

The given parameters are:

\(\mathbf{Blue = 6}\\\\\)

\(\mathbf{Red = 4}\)

\(\mathbf{Yellow = 2}\)

The total number of marbles is:

\(\mathbf{n =Blue + Red + Yellow }\)

\(\mathbf{n =6 + 4 + 2}\)

\(\mathbf{n =12}\)

The probability of selecting 2 blue marbles (with replacement) is:

\(\mathbf{Pr = \frac{Blue}{n} \times \frac{Blue}{n}}\)

\(\mathbf{Pr = \frac{6}{12} \times \frac{6}{12}}\)

Simplify

\(\mathbf{Pr = \frac{1}{2} \times \frac{1}{2}}\)

Multiply

\(\mathbf{Pr = \frac{1}{4}}\)

Hence, the probability of selecting 2 blue marbles (with replacement) is 1/4

Read more about probabilities at:

https://brainly.com/question/11234923