Verified Answer :

Willchemistry

Volume in liters:

139 cm³ / 1000 = 0.139 L   

molar mass Argon = 39.95 g/mol

1 mole -------- 22.4 L ( at STP )
? mole ------- 0.139 L

moles of argon :

0.139 1 / 22.4 = 0.00620 moles 

Mass of argon :

0.00620 39.95 = 0.24769 g

hope this helps!

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