The quantity q varies inversely with the square of m and directly with the product of r and x. When q is 2.5, m is 4 and the product of r and x is 8. What is the constant of variation?


5/8

5/4

5

10

Verified Answer :

q = k (rx)/m^2 ⇒ k = qm^2 /(rx)

k = 2.5 (4)^2 / 8 = 5

Answer: 5

Answer:  Third option is correct.

Step-by-step explanation:

Since we have given that

The quantity q varies inversely with the square of m and directly with the product fo r and x.

According to question,

\(q=k\frac{rx}{m^2}\\\\\text{ where k denotes constant of variation}\)

Since q=2.5, m=4, rx=8,

So, we put the value of all of theses in our above relation:

\(q=k\frac{rx}{m^2}\\\\2.5=k\frac{8}{4^2}\\\\2.5=k\frac{8}{16}\\\\2.5=k\frac{1}{2}\\\\2.5\times 2=k\\\\5=k\)

Hence, Third option is correct.