Answer:
60m (to nearest meter)
Explanation: How far the ball traveled refers to the range covered by the ball before it hits the ground. For an object projected at an angle of ∝ to the horizontal, the range, R covered is given by;
\(R=u^{2}sin2\alpha/2g\)
Where u is the initial velocity and g is acceleration due to gravity.
\(u=26mls\\\alpha=30^{o}\\g=9.81m/s^{2}\)
The value of g could be safely assumed to be \(9.8m/s^{2}\)
Therefore;
\(R=26^{2}sin2(30)/9.8\)
\(R=(26*26*sin60)/9.8\)
\(R=676*0.8660/9.8\)
\(R=59.68m\) which is approximately 60m to nearest meter.
