con1fuselila
Answered

how many real number solutions does the equation have?-8x^2-8x-2=0

1

2

no solutions

or

infinitely many solutions


solve the equation by completing the square. round to the nearest hundredth. x^2+6x=-7

4.41,1.59

-4.41,1.59

-4.41,-1.59

4.41,-1.59


and the last one is

solve the systems of equations algebraically. show all of your steps.

y=x^2+2x

y=3x+20

Verified Answer :

caylus

Hello,

I)
1 solution with multiplicity 2
(2x+1)²=0

II) ANSWER C (-4.41, -1.59)
-3-√2 and -3+√2

III)
y=x²+2x
y=3x+20
==>x²+2x=3x+20
==>x²-x-20=

Δ=1+420=81=9²

(x=(1-9)/2=-4 and y= 3(-4)+20=8 ) or (x=(1+9)/2=5 and y=3*5+20=35)


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