Answer:
First term is 5
Fourth term is 5.5
Tenth term is 6.5
Step-by-step explanation:
Given :The rule as \(A(n)=5+(n-1)(\frac{1}{6})\)
We have to find find the first,fourth,and tenth terms of the arithmetic sequence.
Consider the given rule ,
\(A(n)=5+(n-1)(\frac{1}{6})\)
For first term , put n = 1
\(A(1)=5+(1-1)(\frac{1}{6})\)
Simplify , we have,
\(A(1)=5\)
For fourth term, Put n = 4
we have,
\(A(4)=5+(4-1)(\frac{1}{6})\)
Simplify, we have,
\(A(4)=5+(3)(\frac{1}{6})\)
\(A(4)=5+\frac{1}{2}=5.5\)
For tenth term, put n = 10 ,
We have,
\(A(10)=5+(10-1)(\frac{1}{6})\)
\(A(10)=5+(9)(\frac{1}{6})\)
\(A(4)=5+\frac{3}{2}=6.5\)
Thus, First term is 5
Fourth term is 5.5
Tenth term is 6.5
