solve the simultaneous equation, 5x=2y+1 2x-3y+4+0
Hello,I suppose the 2th equation is 2x-3y+4=05x-2y=1 ........|2 | 32x-3y=-4....... |(-5) | -2==> -4y+15y=2+20==>11y=22==>y=2and 15x-4x=3+8 ==>11x=11 ==>x=1Proof:51=? 22+1 yes21-32+4=? 0 yes (linear combinaison method)