Please help super emergency!!


4.00 x 10^23 molecules of H3PO4 have an approximate mass of

A8g.
B65g.
C147 g.
D663g.

Verified Answer :

1) we can calculate the molecular weight of H₃PO₄
atomic mass  (H)=1 amu
atomic mass (P)=31 amu
atomic mass (O)=16 amu 

molecular weight (H₃PO₄)=3(1)+31+4(16)=98 amu.

1 mol (H₃PO₄)=98 g
1 mol= 6.022 10²³ molecules.

2) we calculate the mass of 4.00
10²³ molecules.

98 g-------------------6.02210²³ molecules
x------------------------4.00
10²³ molecules

x=(98 g 4.0010²³ molecules) / 6.022*10²³ molecules≈65 g

Answer: 65 g