How do the problem h-6+7h=42
\(h-6+7h=42 \\\\ 8h-6=42 \\\\ 8h=42+6 \\\\ 8h=48 \\\\ \boxed{h=\frac{48}{8}=6}\)
solve for h by isolating it on one side and ask else on the other . . .h - 6 + 7h = 42h + 7h - 6 = 42h(1 + 7) - 6 + 6 = 42 + 68h = 488h/8 = 48/8h = 6
