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Choose the correct simplification of the expression a to the 12th power times b to the 8th power all over a to the 2nd power times b to the 4th power.


a10b4


a6b2


1 over a to the 10th power times b to the 4th power


1 over a to the 14th power times b to the 12th power

Verified Answer :

\(\frac{a^{12}b^{8}}{a^{2}b^{4}}\)



remember
(ab)/(cd)=a/c times b/d

also \(\frac{x^{m}}{x^{n}}= x^{m-n}\)

split it up with like terms

\(\frac{a^{12}}{a^{2}}\) times \(\frac{b^{8}}{b^{4}}\)

do subtraction
for a's
12-2=10

b's
8-4=4

answe is \(a^{10}b^{4}\)

first one

Answer:

the first one. a^10b^4

Step-by-step explanation:

i just took the test and double checked it :)