Answer:
Area of cross-section is \(9\pi in^{2}\)
Step-by-step explanation:
Given a cone and a plane parallel to base intersect the cone at the mid point of points between A and B.
We have to find the area of cross-section formed by intersection of the plane and the cone which is a new circle formed.
Given, height=20 in
radius=6 in
By mid point theorem i.e the line segment formed by joining the mid points of two side of triangle is parallel to third equal to half of the third side.
therefore new circle formed is of radius 3 in
Hence, area of cross-section formed by intersection of the plane and the cone which is a new circle formed= \(\pir^{2}\)
= \(3^{2}\pi\)
= \(9\pi\)\(in^{2}\)
