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kaikeemmaashr
kaikeemmaashr kaikeemmaashr
  • 13-05-2016
  • Mathematics
Answered

Factor completely 10xy + 3y + 20ax + 6a.


(10x − 3)(y − 2a)


(10x − 3)(y + 2a)


(10x + 3)(y + 2a)


(10x + 3)(y − 2a)

Verified Answer :

Aivi
Aivi Aivi
  • 18-05-2016

10 xy + 3y + 20 ax + 6a = y(10x+3) + a(20x+6) = y(10x+3)+2a(10x+6)= 
(y+2a)(10x+3)

Answer Link
DelcieRiveria DelcieRiveria
  • 10-05-2019

Answer:

Option 3 is correct.

Step-by-step explanation:

The given expression is

\(10xy+3y+20ax+6a\)

This expression can be written as

\((10xy+3y)+(20ax+6a)\)

Take out the common factors from each parenthesis.

\(y(10x+3)+2a(10x+3)\)

Now, take out the common factor (10x+3).

\((10x+3)(y+2a)\)

Therefore option 3 is correct.

Answer Link

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