Answer:
Image distance of apple=-6.7 cm
Magnification of apple=0.33
Explanation:
We are given that an apple is placed 20.cm in front of a diverging lens.
Object distance=u=-20 cm
Focal length=f=-10 cm
Because focal length of diverging lens is negative.
We have to find the image distance and magnification of the apple.
Lens formula
\(\frac{1}{f}=\frac{1}{v}-\frac{1}{u}\)
Substitute the values then we get
\(-\frac{1}{10}=\frac{1}{v}+\frac{1}{20}\)
\(\frac{1}{v}=-\frac{1}{10}-\frac{1}{20}\)
\(\frac{1}{v}=\frac{-2-1}{20}=-\frac{3}{20}\)
\(v=-\frac{20}{3}=-6.7 cm\)
Image distance of apple=-6.7 cm
Magnification=m=\(\frac{v}{u}=\frac{-\frac{20}{3}}{-20}\)
Magnification of apple=\(\frac{1}{3}=0.33\)
Hence, the magnification of apple=0.33
